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What will be the output of the following C code?
    #include <stdio.h>
    void main()
    {
        int x = 1, y = 0, z = 5;
        int a = x && y && z++;
        printf("%d", z);
    }
  • a)
    6
  • b)
    5
  • c)
    0
  • d)
    Varies
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following C code? #include <stdio.h...
Explanation:

Initialization:
- Three integer variables x, y, and z are initialized to 1, 0, and 5 respectively.

Logical AND operator (&&):
- The logical AND operator (&&) evaluates from left to right. If the left operand is false, the right operand is not evaluated because the result will already be false.
- In this code, x is true (non-zero), y is false (zero), and z is true (non-zero).
- When the expression x && y && z++ is evaluated, since y is false (zero), the right side of the && operator (z++) is not evaluated.
- Therefore, z remains unchanged, and z will be 5 after the evaluation.

Output:
- The value of z is printed using printf function, which is 5.
Therefore, the output of the given code will be:

5
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Community Answer
What will be the output of the following C code? #include <stdio.h...
Yes the correct answer is b because it's 1 x 0 +5x1x1
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